intel: genxml: add script to generate gzipped genxml
[mesa.git] / src / intel / genxml / gen_zipped_file.py
1 #encoding=utf-8
2 #
3 # Copyright © 2017 Intel Corporation
4 #
5 # Permission is hereby granted, free of charge, to any person obtaining a
6 # copy of this software and associated documentation files (the "Software"),
7 # to deal in the Software without restriction, including without limitation
8 # the rights to use, copy, modify, merge, publish, distribute, sublicense,
9 # and/or sell copies of the Software, and to permit persons to whom the
10 # Software is furnished to do so, subject to the following conditions:
11 #
12 # The above copyright notice and this permission notice (including the next
13 # paragraph) shall be included in all copies or substantial portions of the
14 # Software.
15 #
16 # THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
17 # IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
18 # FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL
19 # THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
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21 # FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS
22 # IN THE SOFTWARE.
23 #
24
25 from __future__ import print_function
26 import os
27 import sys
28 import zlib
29
30 def main():
31 if len(sys.argv) < 2:
32 print("No input xml file specified")
33 sys.exit(1)
34
35 with open(sys.argv[1]) as f:
36 compressed_data = zlib.compress(f.read())
37
38 gen_name = os.path.splitext(os.path.basename(sys.argv[1]))[0]
39 print("static const uint8_t %s_xml[] = {" % gen_name)
40 print(" ", end='')
41
42 for i, c in enumerate(compressed_data, start=1):
43 print("0x%.2x, " % ord(c), end='\n ' if not i % 12 else '')
44 print('\n};')
45
46 if __name__ == '__main__':
47 main()