+from sfpy import Float32
+
+
# XXX DO NOT USE, fails on num=65536. wark-wark...
def sqrtsimple(num):
res = 0
for i in range(15, -1, -1): # negative ranges are weird...
if (R>=0):
-
+
R = (R<<2)|((D>>(i+i))&3)
R = R-((Q<<2)|1) #/*-Q01*/
-
+
else:
R = (R<<2)|((D>>(i+i))&3)
R = R+((Q<<2)|3) #/*+Q11*/
-
+
if (R>=0):
Q = (Q<<1)|1 #/*new Q:*/
else:
Q = (Q<<1)|0 #/*new Q:*/
-
+
if (R<0):
R = R+((Q<<1)|1)
ms, es = main(m, e)
print("m:%d e:%d sqrt: m:%d e:%d" % (m, e, ms, es))
+ x = Float32(1234.123456789)
+ xbits = x.bits
+
+ print (x, type(x))
+ print (xbits, type(xbits))
+ s, e, m = decode_fp32(xbits)
+ print(s, e, m, hex(m))
+
+ se, sm = main(e, m)
+ print("our sqrt", se, sm, hex(sm))
+
+ sq_test = x.sqrt()
+ sq_xbits = sq_test.bits
+ s, e, m = decode_fp32(sq_xbits)
+ print ("sf16 sqrt", s, e, m, hex(m))
"""
+
+Notes:
+https://pdfs.semanticscholar.org/5060/4e9aff0e37089c4ab9a376c3f35761ffe28b.pdf
+
//This is the main code of integer sqrt function found here:http://verilogcodes.blogspot.com/2017/11/a-verilog-function-for-finding-square-root.html
//