static uint32_t
total_size(uint8_t cbuf_cpp[], uint8_t zsbuf_cpp[2],
- uint32_t bin_w, uint32_t bin_h, struct fd_gmem_stateobj *gmem)
+ uint32_t bin_w, uint32_t bin_h, uint32_t gmem_align,
+ struct fd_gmem_stateobj *gmem)
{
uint32_t total = 0, i;
for (i = 0; i < MAX_RENDER_TARGETS; i++) {
if (cbuf_cpp[i]) {
- gmem->cbuf_base[i] = align(total, 0x4000);
+ gmem->cbuf_base[i] = align(total, gmem_align);
total = gmem->cbuf_base[i] + cbuf_cpp[i] * bin_w * bin_h;
}
}
if (zsbuf_cpp[0]) {
- gmem->zsbuf_base[0] = align(total, 0x4000);
+ gmem->zsbuf_base[0] = align(total, gmem_align);
total = gmem->zsbuf_base[0] + zsbuf_cpp[0] * bin_w * bin_h;
}
if (zsbuf_cpp[1]) {
- gmem->zsbuf_base[1] = align(total, 0x4000);
+ gmem->zsbuf_base[1] = align(total, gmem_align);
total = gmem->zsbuf_base[1] + zsbuf_cpp[1] * bin_w * bin_h;
}
uint32_t minx, miny, width, height;
uint32_t nbins_x = 1, nbins_y = 1;
uint32_t bin_w, bin_h;
+ uint32_t gmem_align = 0x4000;
uint32_t max_width = bin_width(screen);
uint8_t cbuf_cpp[MAX_RENDER_TARGETS] = {0}, zsbuf_cpp[2] = {0};
uint32_t i, j, t, xoff, yoff;
zsbuf_cpp[0], width, height);
}
+ if (is_a20x(screen) && batch->cleared) {
+ /* under normal circumstances the requirement would be 4K
+ * but the fast clear path requires an alignment of 32K
+ */
+ gmem_align = 0x8000;
+ }
+
/* then find a bin width/height that satisfies the memory
* constraints:
*/
- while (total_size(cbuf_cpp, zsbuf_cpp, bin_w, bin_h, gmem) > gmem_size) {
+ while (total_size(cbuf_cpp, zsbuf_cpp, bin_w, bin_h, gmem_align, gmem) >
+ gmem_size) {
if (bin_w > bin_h) {
nbins_x++;
bin_w = align(width / nbins_x, gmem_alignw);
#define div_round_up(v, a) (((v) + (a) - 1) / (a))
/* figure out number of tiles per pipe: */
- tpp_x = tpp_y = 1;
- while (div_round_up(nbins_y, tpp_y) > screen->num_vsc_pipes)
- tpp_y += 2;
- while ((div_round_up(nbins_y, tpp_y) *
- div_round_up(nbins_x, tpp_x)) > screen->num_vsc_pipes)
- tpp_x += 1;
+ if (is_a20x(ctx->screen)) {
+ /* for a20x we want to minimize the number of "pipes"
+ * binning data has 3 bits for x/y (8x8) but the edges are used to
+ * cull off-screen vertices with hw binning, so we have 6x6 pipes
+ */
+ tpp_x = 6;
+ tpp_y = 6;
+ } else {
+ tpp_x = tpp_y = 1;
+ while (div_round_up(nbins_y, tpp_y) > screen->num_vsc_pipes)
+ tpp_y += 2;
+ while ((div_round_up(nbins_y, tpp_y) *
+ div_round_up(nbins_x, tpp_x)) > screen->num_vsc_pipes)
+ tpp_x += 1;
+ }
gmem->maxpw = tpp_x;
gmem->maxph = tpp_y;
xoff += tpp_x;
}
+ /* number of pipes to use for a20x */
+ gmem->num_vsc_pipes = MAX2(1, i);
+
for (; i < npipes; i++) {
struct fd_vsc_pipe *pipe = &ctx->vsc_pipe[i];
pipe->x = pipe->y = pipe->w = pipe->h = 0;
/* pipe number: */
p = ((i / tpp_y) * div_round_up(nbins_x, tpp_x)) + (j / tpp_x);
+ assert(p < gmem->num_vsc_pipes);
/* clip bin width: */
bw = MIN2(bin_w, minx + width - xoff);
-
- tile->n = tile_n[p]++;
+ tile->n = !is_a20x(ctx->screen) ? tile_n[p]++ :
+ ((i % tpp_y + 1) << 3 | (j % tpp_x + 1));
tile->p = p;
tile->bin_w = bw;
tile->bin_h = bh;