Tweak the way that is_a is implemented
At the moment, class hierarchies that use is_a are expected
to define specialisations like:
template <>
template <>
inline bool
is_a_helper <cgraph_node *>::test (symtab_node *p)
{
return p->type == SYMTAB_FUNCTION;
}
But this doesn't scale well to larger hierarchies, because it only
defines ::test for an argument that is exactly “symtab_node *”
(and not for example “const symtab_node *” or something that
comes between cgraph_node and symtab_node in the hierarchy).
For example:
struct A { int x; };
struct B : A {};
struct C : B {};
template <>
template <>
inline bool
is_a_helper <C *>::test (A *a)
{
return a->x == 1;
}
bool f(B *b) { return is_a<C *> (b); }
gives:
warning: inline function ‘static bool is_a_helper<T>::test(U*) [with U = B; T = C*]’ used but never defined
and:
bool f(const A *a) { return is_a<const C *> (a); }
gives:
warning: inline function ‘static bool is_a_helper<T>::test(U*) [with U = const A; T = const C*]’ used but never defined
This patch instead allows is_a to be implemented by specialising
is_a_helper as a whole, for example:
template<>
struct is_a_helper<C *> : static_is_a_helper<C *>
{
static inline bool test (const A *a) { return a->x == 1; }
};
It also adds a general specialisation of is_a_helper for const
pointers. Together, this makes both of the above examples work.
gcc/
* is-a.h (reinterpret_is_a_helper): New class.
(static_is_a_helper): Likewise.
(is_a_helper): Inherit from reinterpret_is_a_helper.
(is_a_helper<const T *>): New specialization.