draw: Allocate the output buffer for output primitives

We were allocating the output buffer but using the input
primitives. We need to allocate that buffer using the
maximum number of output, not input, primitives.

Signed-off-by: Zack Rusin <zackr@vmware.com>
Reviewed-by: Brian Paul <brianp@vmware.com>
Reviewed-by: José Fonseca <jfonseca@vmware.com>

diff --git a/src/gallium/auxiliary/draw/draw_gs.c b/src/gallium/auxiliary/draw/draw_gs.c
index c8ed95ae7d39b2eb1fd6f00f26948253c1c54eed..0115d4716a1c7d87b77f3d5bdf6889f66ceb955c 100644 (file)
--- a/src/gallium/auxiliary/draw/draw_gs.c
+++ b/src/gallium/auxiliary/draw/draw_gs.c
@@ -506,10 +506,9 @@ int draw_geometry_shader_run(struct draw_geometry_shader *shader,
    output_verts->stride = output_verts->vertex_size;
    output_verts->verts =
       (struct vertex_header *)MALLOC(output_verts->vertex_size *
-                                     num_in_primitives *
+                                     max_out_prims *
                                      shader->max_output_vertices);
 
-
 #if 0
    debug_printf("%s count = %d (in prims # = %d)\n",
                 __FUNCTION__, num_input_verts, num_in_primitives);