It doesn't matter whether a write is saturated or not, in another
implementation it might even have been a separate opcode. This code was
most likely copied from the copy-propagation pass (where one does have
to distinguish saturation).
Signed-off-by: Ilia Mirkin <imirkin@alum.mit.edu>
Reviewed-by: Marek Olšák <marek.olsak@amd.com>
*/
for (unsigned i = 0; i < ARRAY_SIZE(inst->dst); i++) {
if (inst->dst[i].file == PROGRAM_TEMPORARY &&
- !inst->dst[i].reladdr &&
- !inst->saturate) {
+ !inst->dst[i].reladdr) {
for (int c = 0; c < 4; c++) {
if (inst->dst[i].writemask & (1 << c)) {
if (writes[4 * inst->dst[i].index + c]) {