The next patch adds an algebraic rule that uses the constant 0xff00ff00.
Without this change, the build fails with
return hex(struct.unpack('I', struct.pack('i', self.value))[0])
struct.error: 'i' format requires -
2147483648 <= number <=
2147483647
The hex() function handles integers of any size, and assigning a
negative value to an unsigned does what we want in C. The pack/unpack is
unnecessary (and as we see, buggy).
Reviewed-by: Dylan Baker <baker.dylan.c@gmail.com>
self.value = val
def __hex__(self):
- # Even if it's an integer, we still need to unpack as an unsigned
- # int. This is because, without C99, we can only assign to the first
- # element of a union in an initializer.
if isinstance(self.value, (bool)):
return 'NIR_TRUE' if self.value else 'NIR_FALSE'
if isinstance(self.value, (int, long)):
- return hex(struct.unpack('I', struct.pack('i', self.value))[0])
+ return hex(self.value)
elif isinstance(self.value, float):
return hex(struct.unpack('I', struct.pack('f', self.value))[0])
else: