bool enum_ok)
{
tree decl;
- tree scope;
- bool typename_p;
- cp_token *token;
tree identifier = NULL_TREE;
/* All class-names start with an identifier. */
- token = cp_lexer_peek_token (parser->lexer);
+ cp_token *token = cp_lexer_peek_token (parser->lexer);
if (token->type != CPP_NAME && token->type != CPP_TEMPLATE_ID)
{
cp_parser_error (parser, "expected class-name");
where we first want to look up A<T>::a in the class of the object
expression, as per [basic.lookup.classref]. */
- scope = parser->scope ? parser->scope : parser->context->object_type;
+ tree scope = parser->scope ? parser->scope : parser->context->object_type;
if (scope == error_mark_node)
return error_mark_node;
/* Any name names a type if we're following the `typename' keyword
in a qualified name where the enclosing scope is type-dependent. */
- typename_p = (typename_keyword_p && scope && TYPE_P (scope)
- && dependent_type_p (scope));
+ const bool typename_p = (typename_keyword_p
+ && parser->scope
+ && TYPE_P (parser->scope)
+ && dependent_type_p (parser->scope));
/* Handle the common case (an identifier, but not a template-id)
efficiently. */
if (token->type == CPP_NAME
--- /dev/null
+// PR c++/94799
+// { dg-do compile { target c++11 } }
+
+template <typename> struct A {
+ typedef int type;
+ operator int();
+};
+
+template <typename T> using B = A<T>;
+
+template <typename T> typename B<T>::type foo(B<T> b)
+{
+ auto r1 = b.operator typename A<T>::type();
+ auto r2 = b.operator typename A<T>::template A<T>::type();
+ auto r3 = b.operator typename B<T>::type();
+ auto r4 = b.operator typename B<T>::template A<T>::type();
+ return r1 + r2 + r3 + r4;
+}
+
+void bar()
+{
+ foo(A<int>());
+}