When a numeric literal with leading zeroes was seen in the parser, it
would only be accepted if it were a valid hex or octal literal. Any
invalid numeric literal would be split up into multiple tokens: the
valid hex/octal literal followed by the rest of the characters.
Instead, when scanning a numeric literal with leading zeroes, always
accept the number and give an appropriate error if the accepted number
does not fit in the expected base.
Fixes golang/go#11532, golang/go#11533.
Reviewed-on: https://go-review.googlesource.com/13791
From-SVN: r227193
-14ca4b6130b9a7132d132f418e9ea283b3a52c08
+f97d579fa8431af5cfde9b0a48604caabfd09377
The first line of this file holds the git revision number of the last
merge done from the gofrontend repository.
pnum = p;
while (p < pend)
{
- if (*p < '0' || *p > '7')
+ if (*p < '0' || *p > '9')
break;
++p;
}
std::string s(pnum, p - pnum);
mpz_t val;
int r = mpz_init_set_str(val, s.c_str(), base);
- go_assert(r == 0);
+ if (r != 0)
+ {
+ if (base == 8)
+ error_at(this->location(), "invalid octal literal");
+ else
+ error_at(this->location(), "invalid hex literal");
+ }
if (neg)
mpz_neg(val, val);