case R_V850_LO16:
/* Calculate the sum of the value stored in the instruction and the
addend and check for overflow from the low 16 bits into the high
- 16 bits. This can occur if the computation sets the 16th bit when
- before it was clear, since the 16th bit will be sign extended into
- the high part, thus reducing its value by one, but since the 16th bit
- was originally clear, the previous R_V850_HI16_S relocation will not
- have added in an additional 1 to the high part to compensate for this
- effect. Overflow can also occur if the compuation carries into the
- 17th bit and it also results in the 16th bit having the same value as
- the 16th bit of the original value. What happens is that the
- R_V850_HI16_S relocation will have already examined the 16th bit of
- the original value and added 1 to the high part if the bit is set.
- This compensates for the sign extension of 16th bit of the result of
- the computation. But now there is a carry into the 17th bit, and this
- has not been allowed for. Note - there is no need to change anything
- if a carry occurs, and the 16th bit changes its value, (this can only
- happen if the bit was set in the original value, but is clear in the
- result of the computation), as the R_V850_HI16_S relocation will have
- already added in 1 to the high part for us. Here are some examples:
-
- original value = 0x12345
- addend = 0x01234
- -------
- 0x13579 => R_V850_HI16_S stores 0x0001
- R_V850_LO16 stores 0x3579
-
- This is OK.
-
- original value = 0x12345
- addend = 0x07000
- -------
- 0x19345 => R_V850_HI16_S stores 0x0001
- R_V850_LO16 stores 0x9345
-
- but the 0x9345 value gets sign
- extended, so the sum becomes:
-
- 0x00010000
- 0xffff9345
- ----------
- 0x00009345 which is wrong.
-
- This is the first example of overflow.
-
- original value = 0x18888
- addend = 0x08888
- -------
- 0x21110 => R_V850_HI16_S stores 0x0002 (because 16th bit of the original value is set)
- R_V850_LO16 stores 0x1110
-
- and the sum is now:
-
- 0x00020000
- 0x00001110
- ----------
- 0x00021110 which is OK.
-
- original value = 0x1ffff
- addend = 0x08888
- -------
- 0x28887 => R_V850_HI16_S stores 0x0002
- R_V850_LO16 stores 0x8887
-
- and the sum is now:
-
- 0x00020000
- 0xffff8887
- ----------
- 0x00018887 which is wrong.
-
- This is the second example of overflow.
- (The 16th bit remains set).
-
- original value = 0x15555
- addend = 0x0ffff
- -------
- 0x25554 => R_V850_HI16_S stores 0x0001
- R_V850_LO16 stores 0x5554
-
- the sum is now:
-
- 0x00010000
- 0x00005554
- ----------
- 0x00015554 which is wrong.
-
- This is the other form of the second
- example of overflow. (The 16th bit
- remains clear)
+ 16 bits. The assembler has already done some of this: If the
+ value stored in the instruction has its 15th bit set, then the
+ assembler will have added 1 to the value stored in the associated
+ HI16S reloc. So for example, these relocations:
+
+ movhi hi( fred ), r0, r1
+ movea lo( fred ), r1, r1
+
+ will store 0 in the value fields for the MOVHI and MOVEA instructions
+ and addend will be the address of fred, but for these instructions:
+
+ movhi hi( fred + 0x123456), r0, r1
+ movea lo( fred + 0x123456), r1, r1
+
+ the value stored in the MOVHI instruction will be 0x12 and the value
+ stored in the MOVEA instruction will be 0x3456. If however the
+ instructions were:
+
+ movhi hi( fred + 0x10ffff), r0, r1
+ movea lo( fred + 0x10ffff), r1, r1
+
+ then the value stored in the MOVHI instruction would be 0x11 (not
+ 0x10) and the value stored in the MOVEA instruction would be 0xffff.
+ Thus (assuming for the moment that the addend is 0), at run time the
+ MOVHI instruction loads 0x110000 into r1, then the MOVEA instruction
+ adds 0xffffffff (sign extension!) producing 0x10ffff. Similarly if
+ the instructions were:
+
+ movhi hi( fred - 1), r0, r1
+ movea lo( fred - 1), r1, r1
+
+ then 0 is stored in the MOVHI instruction and -1 is stored in the
+ MOVEA instruction.
+
+ Overflow can occur if the addition of the value stored in the
+ instruction plus the addend sets the 15th bit (counting from 0) when
+ before it was clear. This is because the 15th bit will be sign
+ extended into the high part, thus reducing its value by one, but
+ since the 15th bit was originally clear, the previous HI16S
+ relocation will not have added in an additional 1 to the high part
+ to compensate for this effect. For example:
+
+ movhi hi( fred + 0x123456), r0, r1
+ movea lo( fred + 0x123456), r1, r1
+
+ The value stored in HI16S reloc is 0x12, the value stored in the LO16
+ reloc is 0x3456. If we assume that the address of fred is 0x00007000
+ then the relocations become:
+
+ HI16S: 0x0012 + (0x00007000 >> 16) = 0x12
+ LO16: 0x3456 + (0x00007000 & 0xffff) = 0xa456
+
+ but when the instructions are executed, the MOVEA instruction's value
+ is signed extended, so the sum becomes:
+
+ 0x00120000
+ + 0xffffa456
+ ------------
+ 0x0011a456 but 'fred + 0x123456' = 0x0012a456
+
+ Note that if the 15th bit was set in the value stored in the LO16
+ reloc, then we do not have to do anything:
+
+ movhi hi( fred + 0x10ffff), r0, r1
+ movea lo( fred + 0x10ffff), r1, r1
+
+ HI16S: 0x0011 + (0x00007000 >> 16) = 0x11
+ LO16: 0xffff + (0x00007000 & 0xffff) = 0x6fff
+
+ 0x00110000
+ + 0x00006fff
+ ------------
+ 0x00116fff = fred + 0x10ffff = 0x7000 + 0x10ffff
+
+
+ Overflow can also occur if the computation carries into the 16th bit
+ and it also results in the 15th bit having the same value as the 15th
+ bit of the original value. What happens is that the HI16S reloc
+ will have already examined the 15th bit of the original value and
+ added 1 to the high part if the bit is set. This compensates for the
+ sign extension of 15th bit of the result of the computation. But now
+ there is a carry into the 16th bit, and this has not been allowed for.
+
+ So, for example if fred is at address 0xf000:
+
+ movhi hi( fred + 0xffff), r0, r1 [bit 15 of the offset is 1]
+ movea lo( fred + 0xffff), r1, r1
+
+ HI16S: 0x0001 + (0x0000f000 >> 16) = 0x0001
+ LO16: 0xffff + (0x0000f000 & 0xffff) = 0xefff (carry into bit 16)
+
+ 0x00010000
+ + 0xffffefff
+ ------------
+ 0x0000efff but 'fred + 0xffff' = 0x0001efff
+
+ Similarly, if the 15th bit remains clear, but overflow occurs into
+ the 16th bit then (assuming the address of fred is 0xf000):
+
+ movhi hi( fred + 0x7000), r0, r1 [bit 15 of the offset is 0]
+ movea lo( fred + 0x7000), r1, r1
+
+ HI16S: 0x0000 + (0x0000f000 >> 16) = 0x0000
+ LO16: 0x7000 + (0x0000f000 & 0xffff) = 0x6fff (carry into bit 16)
+
+ 0x00000000
+ + 0x00006fff
+ ------------
+ 0x00006fff but 'fred + 0x7000' = 0x00016fff
+
+ Note - there is no need to change anything if a carry occurs, and the
+ 15th bit changes its value from being set to being clear, as the HI16S
+ reloc will have already added in 1 to the high part for us:
+
+ movhi hi( fred + 0xffff), r0, r1 [bit 15 of the offset is 1]
+ movea lo( fred + 0xffff), r1, r1
+
+ HI16S: 0x0001 + (0x00007000 >> 16)
+ LO16: 0xffff + (0x00007000 & 0xffff) = 0x6fff (carry into bit 16)
+
+ 0x00010000
+ + 0x00006fff (bit 15 not set, so the top half is zero)
+ ------------
+ 0x00016fff which is right (assuming that fred is at 0x7000)
+
+ but if the 15th bit goes from being clear to being set, then we must
+ once again handle overflow:
+
+ movhi hi( fred + 0x7000), r0, r1 [bit 15 of the offset is 0]
+ movea lo( fred + 0x7000), r1, r1
+
+ HI16S: 0x0000 + (0x0000ffff >> 16)
+ LO16: 0x7000 + (0x0000ffff & 0xffff) = 0x6fff (carry into bit 16)
+
+ 0x00000000
+ + 0x00006fff (bit 15 not set, so the top half is zero)
+ ------------
+ 0x00006fff which is wrong (assuming that fred is at 0xffff)
*/
{
long result;
-
+
insn = bfd_get_16 (abfd, address);
result = insn + addend;
-#define BIT16_SET(x) ((x) & 0x8000)
-#define OVERFLOWS(a,i) (((a) & 0xffff) + (i) > 0xffff)
+#define BIT15_SET(x) ((x) & 0x8000)
+#define OVERFLOWS(a,i) ((((a) & 0xffff) + (i)) > 0xffff)
- if ((BIT16_SET (result) && ! BIT16_SET (addend))
- || (OVERFLOWS (addend, insn)
- && (BIT16_SET (result) == BIT16_SET (addend))))
+ if ((BIT15_SET (result) && ! BIT15_SET (addend))
+ || (OVERFLOWS (addend, insn)
+ && ((! BIT15_SET (insn)) || (BIT15_SET (addend)))))
{
/* Amend the preceding HI16_S relocation, allowing for
an intervening instruction, which does occasionally happen. */