/* The Variable. */
tree decl;
- /* The offset of the variable. During partitioning, this is the
- offset relative to the partition. After partitioning, this
- is relative to the stack frame. */
- HOST_WIDE_INT offset;
-
/* Initially, the size of the variable. Later, the size of the partition,
if this variable becomes it's partition's representative. */
HOST_WIDE_INT size;
v = &stack_vars[stack_vars_num];
v->decl = decl;
- v->offset = 0;
v->size = tree_low_cst (DECL_SIZE_UNIT (SSAVAR (decl)), 1);
/* Ensure that all variables have size, so that &a != &b for any two
variables that are simultaneously live. */
return (int)largeb - (int)largea;
/* Secondary compare on size, decreasing */
- if (sizea < sizeb)
- return -1;
if (sizea > sizeb)
+ return -1;
+ if (sizea < sizeb)
return 1;
/* Tertiary compare on true alignment, decreasing. */
/* A subroutine of partition_stack_vars. The UNION portion of a UNION/FIND
partitioning algorithm. Partitions A and B are known to be non-conflicting.
- Merge them into a single partition A.
-
- At the same time, add OFFSET to all variables in partition B. At the end
- of the partitioning process we've have a nice block easy to lay out within
- the stack frame. */
+ Merge them into a single partition A. */
static void
-union_stack_vars (size_t a, size_t b, HOST_WIDE_INT offset)
+union_stack_vars (size_t a, size_t b)
{
- size_t i, last;
struct stack_var *vb = &stack_vars[b];
bitmap_iterator bi;
unsigned u;
- /* Update each element of partition B with the given offset,
- and merge them into partition A. */
- for (last = i = b; i != EOC; last = i, i = stack_vars[i].next)
- {
- stack_vars[i].offset += offset;
- stack_vars[i].representative = a;
- }
- stack_vars[last].next = stack_vars[a].next;
+ gcc_assert (stack_vars[b].next == EOC);
+ /* Add B to A's partition. */
+ stack_vars[b].next = stack_vars[a].next;
+ stack_vars[b].representative = a;
stack_vars[a].next = b;
/* Update the required alignment of partition A to account for B. */
partitions constrained by the interference graph. The overall
algorithm used is as follows:
- Sort the objects by size.
+ Sort the objects by size in descending order.
For each object A {
S = size(A)
O = 0
loop {
Look for the largest non-conflicting object B with size <= S.
UNION (A, B)
- offset(B) = O
- O += size(B)
- S -= size(B)
}
}
*/
for (si = 0; si < n; ++si)
{
size_t i = stack_vars_sorted[si];
- HOST_WIDE_INT isize = stack_vars[i].size;
unsigned int ialign = stack_vars[i].alignb;
- HOST_WIDE_INT offset = 0;
- for (sj = si; sj-- > 0; )
+ /* Ignore objects that aren't partition representatives. If we
+ see a var that is not a partition representative, it must
+ have been merged earlier. */
+ if (stack_vars[i].representative != i)
+ continue;
+
+ for (sj = si + 1; sj < n; ++sj)
{
size_t j = stack_vars_sorted[sj];
- HOST_WIDE_INT jsize = stack_vars[j].size;
unsigned int jalign = stack_vars[j].alignb;
/* Ignore objects that aren't partition representatives. */
if (stack_vars[j].representative != j)
continue;
- /* Ignore objects too large for the remaining space. */
- if (isize < jsize)
- continue;
-
/* Ignore conflicting objects. */
if (stack_var_conflict_p (i, j))
continue;
!= (jalign * BITS_PER_UNIT <= MAX_SUPPORTED_STACK_ALIGNMENT))
continue;
- /* Refine the remaining space check to include alignment. */
- if (offset & (jalign - 1))
- {
- HOST_WIDE_INT toff = offset;
- toff += jalign - 1;
- toff &= -(HOST_WIDE_INT)jalign;
- if (isize - (toff - offset) < jsize)
- continue;
-
- isize -= toff - offset;
- offset = toff;
- }
-
/* UNION the objects, placing J at OFFSET. */
- union_stack_vars (i, j, offset);
-
- isize -= jsize;
- if (isize == 0)
- break;
+ union_stack_vars (i, j);
}
}
{
fputc ('\t', dump_file);
print_generic_expr (dump_file, stack_vars[j].decl, dump_flags);
- fprintf (dump_file, ", offset " HOST_WIDE_INT_PRINT_DEC "\n",
- stack_vars[j].offset);
}
+ fputc ('\n', dump_file);
}
}
partition. */
for (j = i; j != EOC; j = stack_vars[j].next)
{
- gcc_assert (stack_vars[j].offset <= stack_vars[i].size);
expand_one_stack_var_at (stack_vars[j].decl,
base, base_align,
- stack_vars[j].offset + offset);
+ offset);
}
}