As described in C++ reference [1], static data members are not part
of objects of a given class type. Modified compute_struct_member ()
to ignore static data member so that we can get the expected result.
loongson@linux:~$ cat test.c
#include<stdio.h>
struct struct_01 { static unsigned a; float b;};
unsigned struct_01::a = 66;
struct struct_01 struct_01_val = { 99.00 };
int check_arg_struct(struct struct_01 arg)
{
printf("arg.a = %d\n", arg.a);
printf("arg.b = %f\n", arg.b);
return 0;
}
int main()
{
check_arg_struct(struct_01_val);
return 0;
}
loongson@linux:~$ g++ -g test.c -o test++
loongson@linux:~$ gdb test++
Without this patch:
...
(gdb) start
...
(gdb) p check_arg_struct(struct_01_val)
arg.a = 66
arg.b = 0.000000
$1 = 0
With this patch:
...
(gdb) start
...
(gdb) p check_arg_struct(struct_01_val)
arg.a = 66
arg.b = 99.000000
$1 = 0
[1] https://learn.microsoft.com/en-us/cpp/cpp/static-members-cpp?view=msvc-170
Signed-off-by: Hui Li <lihui@loongson.cn>
Reviewed-By: Tom Tromey <tom@tromey.com>
Signed-off-by: Tiezhu Yang <yangtiezhu@loongson.cn>
{
for (int i = 0; i < type->num_fields (); i++)
{
+ /* Ignore any static fields. */
+ if (field_is_static (&type->field (i)))
+ continue;
+
struct type *field_type = check_typedef (type->field (i).type ());
if (field_type->code () == TYPE_CODE_INT