The rot agent expression bytecode rotates the three items on the top of
the stack. It is not clear which way the rotation is. However, the
documentation currently shows this as the effect of the instructions:
a b c => c b a
which doesn't make sense, since the value b doesn't move. The two
valid possibilities I see are
a b c => b c a
a b c => c a b
depending on which way you rotate.
When looking at the gdbserver code, the top of the stack becomes the
third item, and the next-to-top item becomes the top. So the second
form would be the right one, since in this notation the top of the stack
is the rightmost element:
a b c => c a b
I adjusted the symbolic description and added a bit of text to make it
more obvious.
gdb/doc/ChangeLog:
* agentexpr.texi (rot): Fix symbolic description, improve
textual description.
+2017-07-31 Simon Marchi <simon.marchi@ericsson.com>
+
+ * agentexpr.texi (rot): Fix symbolic description, improve
+ textual description.
+
2017-07-26 Yao Qi <yao.qi@linaro.org>
* gdb.texinfo (Maintenance Commands): Document command
the item under the top item, etc. If @var{n} exceeds the number of
items on the stack, terminate with an error.
-@item @code{rot} (0x33): @var{a} @var{b} @var{c} => @var{c} @var{b} @var{a}
-Rotate the top three items on the stack.
+@item @code{rot} (0x33): @var{a} @var{b} @var{c} => @var{c} @var{a} @var{b}
+Rotate the top three items on the stack. The top item (c) becomes the third
+item, the next-to-top item (b) becomes the top item and the third item (a) from
+the top becomes the next-to-top item.
@item @code{if_goto} (0x20) @var{offset}: @var{a} @result{}
Pop an integer off the stack; if it is non-zero, branch to the given