@@ -123,7+123,7 @@ therefore the strategy proposed is:
with 2x12 this would mean no need to have complex encoding of swizzle.
-if we really do need 2 bits spare then the complex encoder of swizzle could be deployed.
+if we really do need 2 bits spare then the complex encoder of swizzle could be deployed. (*an analysis shows this to be very unlikely. 7^4 is around 2400 which still requires 12 bits to encode)