tree
cp_expr_size (tree exp)
{
- if (CLASS_TYPE_P (TREE_TYPE (exp)))
+ tree type = TREE_TYPE (exp);
+
+ if (CLASS_TYPE_P (type))
{
/* The backend should not be interested in the size of an expression
of a type with both of these set; all copies of such types must go
through a constructor or assignment op. */
- gcc_assert (!TYPE_HAS_COMPLEX_INIT_REF (TREE_TYPE (exp))
- || !TYPE_HAS_COMPLEX_ASSIGN_REF (TREE_TYPE (exp))
+ gcc_assert (!TYPE_HAS_COMPLEX_INIT_REF (type)
+ || !TYPE_HAS_COMPLEX_ASSIGN_REF (type)
/* But storing a CONSTRUCTOR isn't a copy. */
- || TREE_CODE (exp) == CONSTRUCTOR);
+ || TREE_CODE (exp) == CONSTRUCTOR
+ /* And, the gimplifier will sometimes make a copy of
+ an aggregate. In particular, for a case like:
+
+ struct S { S(); };
+ struct X { int a; S s; };
+ X x = { 0 };
+
+ the gimplifier will create a temporary with
+ static storage duration, perform static
+ initialization of the temporary, and then copy
+ the result. Since the "s" subobject is never
+ constructed, this is a valid transformation. */
+ || CP_AGGREGATE_TYPE_P (type));
/* This would be wrong for a type with virtual bases, but they are
caught by the assert above. */
- return (is_empty_class (TREE_TYPE (exp))
+ return (is_empty_class (type)
? size_zero_node
- : CLASSTYPE_SIZE_UNIT (TREE_TYPE (exp)));
+ : CLASSTYPE_SIZE_UNIT (type));
}
else
/* Use the default code. */