along with this program; if not, write to the Free Software
Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA. */
-/* Notes on the algorithm used in wait_for_inferior to determine if we
- just did a subroutine call when stepping. We have the following
- information at that point:
-
- Current and previous (just before this step) pc.
- Current and previous sp.
- Current and previous start of current function.
-
- If the starts of the functions don't match, then
-
- a) We did a subroutine call.
-
- In this case, the pc will be at the beginning of a function.
-
- b) We did a subroutine return.
-
- Otherwise.
-
- c) We did a longjmp.
-
- If we did a longjump, we were doing "nexti", since a next would
- have attempted to skip over the assembly language routine in which
- the longjmp is coded and would have simply been the equivalent of a
- continue. I consider this ok behaivior. We'd like one of two
- things to happen if we are doing a nexti through the longjmp()
- routine: 1) It behaves as a stepi, or 2) It acts like a continue as
- above. Given that this is a special case, and that anybody who
- thinks that the concept of sub calls is meaningful in the context
- of a longjmp, I'll take either one. Let's see what happens.
-
- Acts like a subroutine return. I can handle that with no problem
- at all.
-
- -->So: If the current and previous beginnings of the current
- function don't match, *and* the pc is at the start of a function,
- we've done a subroutine call. If the pc is not at the start of a
- function, we *didn't* do a subroutine call.
-
- -->If the beginnings of the current and previous function do match,
- either:
-
- a) We just did a recursive call.
-
- In this case, we would be at the very beginning of a
- function and 1) it will have a prologue (don't jump to
- before prologue, or 2) (we assume here that it doesn't have
- a prologue) there will have been a change in the stack
- pointer over the last instruction. (Ie. it's got to put
- the saved pc somewhere. The stack is the usual place. In
- a recursive call a register is only an option if there's a
- prologue to do something with it. This is even true on
- register window machines; the prologue sets up the new
- window. It might not be true on a register window machine
- where the call instruction moved the register window
- itself. Hmmm. One would hope that the stack pointer would
- also change. If it doesn't, somebody send me a note, and
- I'll work out a more general theory.
- bug-gdb@prep.ai.mit.edu). This is true (albeit slipperly
- so) on all machines I'm aware of:
-
- m68k: Call changes stack pointer. Regular jumps don't.
-
- sparc: Recursive calls must have frames and therefor,
- prologues.
-
- vax: All calls have frames and hence change the
- stack pointer.
-
- b) We did a return from a recursive call. I don't see that we
- have either the ability or the need to distinguish this
- from an ordinary jump. The stack frame will be printed
- when and if the frame pointer changes; if we are in a
- function without a frame pointer, it's the users own
- lookout.
-
- c) We did a jump within a function. We assume that this is
- true if we didn't do a recursive call.
-
- d) We are in no-man's land ("I see no symbols here"). We
- don't worry about this; it will make calls look like simple
- jumps (and the stack frames will be printed when the frame
- pointer moves), which is a reasonably non-violent response.
-*/
-
#include "defs.h"
#include <string.h>
#include <ctype.h>
SKIP_PROLOGUE (prologue_pc);
}
- /* ==> See comments at top of file on this algorithm. <==*/
+ if ((/* Might be a non-recursive call. If the symbols are missing
+ enough that stop_func_start == prev_func_start even though
+ they are really two functions, we will treat some calls as
+ jumps. */
+ stop_func_start != prev_func_start
+
+ /* Might be a recursive call if either we have a prologue
+ or the call instruction itself saves the PC on the stack. */
+ || prologue_pc != stop_func_start
+ || stop_sp != prev_sp)
+ && (/* I think this can only happen if stop_func_start is zero
+ (e.g. stop_pc is in some objfile we don't know about).
+ If the stop_pc does that (ends up someplace unknown), it
+ must be some sort of subroutine call. */
+ stop_pc < stop_func_start
+ || stop_pc >= stop_func_end
+
+ /* If we do a call, we will be at the start of a function. */
+ || stop_pc == stop_func_start
+
+#if 0
+ /* Not conservative enough for 4.11. FIXME: enable this
+ after 4.11. */
+ /* Except on the Alpha with -O (and perhaps other machines
+ with similar calling conventions), in which we might
+ call the address after the load of gp. Since prologues
+ don't contain calls, we can't return to within one, and
+ we don't jump back into them, so this check is OK. */
+ || stop_pc < prologue_pc
+#endif
- if ((stop_pc < stop_func_start
- || stop_pc >= stop_func_end
- || stop_pc == stop_func_start
- || IN_SOLIB_TRAMPOLINE (stop_pc, stop_func_name))
- && (stop_func_start != prev_func_start
- || prologue_pc != stop_func_start
- || stop_sp != prev_sp))
+ /* If we end up in certain places, it means we did a subroutine
+ call. I'm not completely sure this is necessary now that we
+ have the above checks with stop_func_start (and now that
+ find_pc_partial_function is pickier. */
+ || IN_SOLIB_TRAMPOLINE (stop_pc, stop_func_name)
+
+ /* If none of the above apply, it is a jump within a function,
+ or a return from a subroutine. The other case is longjmp,
+ which can no longer happen here as long as the
+ handling_longjmp stuff is working. */
+ ))
{
/* It's a subroutine call. */
projects / binutils-gdb.git / commitdiff