python: Explicitly use a list

On Python 2, the builtin functions filter() returns a list.

On Python 3, it returns an iterator.

Since we want to use those objects in contexts where we need lists, we
need to explicitly turn them into lists.

This makes the code compatible with both Python 2 and Python 3.

Signed-off-by: Mathieu Bridon <bochecha@daitauha.fr>
Reviewed-by: Dylan Baker <dylan@pnwbakers.com>

diff --git a/src/mesa/main/get_hash_generator.py b/src/mesa/main/get_hash_generator.py
index facdccd8a53f3637686dbc2a145baf9f31bf06f0..37dae45e0b39f06be6a25e334c2203326086e7ff 100644 (file)
--- a/src/mesa/main/get_hash_generator.py
+++ b/src/mesa/main/get_hash_generator.py
@@ -117,8 +117,8 @@ def print_tables(tables):
 def merge_tables(tables):
    merged_tables = []
    for api, indices in sorted(tables.items()):
-      matching_table = filter(lambda mt:mt["indices"] == indices,
-                              merged_tables)
+      matching_table = list(filter(lambda mt:mt["indices"] == indices,
+                              merged_tables))
       if matching_table:
          matching_table[0]["apis"].append(api)
       else: