1/ln(2) is equivalent to log2(e), so define it as such.
log2(e) = ln(e)/ln(2) = 1/ln(2)
Worst of all, the definitions for M_LOG2E and ONE_DIV_LN2
(right beside each other!) weren't the same.
Reviewed-by: Alex Deucher <alexdeucher@gmail.com>
Signed-off-by: Matt Turner <mattst88@gmail.com>
Signed-off-by: Brian Paul <brianp@vmware.com>
#define M_LOG2E (1.4426950408889634074)
#endif
-#ifndef ONE_DIV_LN2
-#define ONE_DIV_LN2 (1.442695040888963456)
-#endif
-
#ifndef ONE_DIV_SQRT_LN2
#define ONE_DIV_SQRT_LN2 (1.201122408786449815)
#endif
value[0] = (ctx->Fog.End == ctx->Fog.Start)
? 1.0f : (GLfloat)(-1.0F / (ctx->Fog.End - ctx->Fog.Start));
value[1] = ctx->Fog.End * -value[0];
- value[2] = (GLfloat)(ctx->Fog.Density * ONE_DIV_LN2);
+ value[2] = (GLfloat)(ctx->Fog.Density * M_LOG2E); /* M_LOG2E == 1/ln(2) */
value[3] = (GLfloat)(ctx->Fog.Density * ONE_DIV_SQRT_LN2);
return;