switch (TREE_CODE (exp))
{
case CONVERT_EXPR:
+ case VIEW_CONVERT_EXPR:
case NOP_EXPR:
case NON_LVALUE_EXPR:
/* Conversions between pointers and integers don't change the alignment
this_alignment = known_alignment (TREE_OPERAND (exp, 0));
break;
+ case COMPOUND_EXPR:
+ /* The value of a COMPOUND_EXPR is that of it's second operand. */
+ this_alignment = known_alignment (TREE_OPERAND (exp, 1));
+ break;
+
case PLUS_EXPR:
case MINUS_EXPR:
/* If two address are added, the alignment of the result is the
this_alignment = MIN (lhs, rhs);
break;
+ case COND_EXPR:
+ /* If there is a choice between two values, use the smallest one. */
+ lhs = known_alignment (TREE_OPERAND (exp, 1));
+ rhs = known_alignment (TREE_OPERAND (exp, 2));
+ this_alignment = MIN (lhs, rhs);
+ break;
+
case INTEGER_CST:
/* The first part of this represents the lowest bit in the constant,
but is it in bytes, not bits. */
this_alignment = MIN (BIGGEST_ALIGNMENT, lhs * rhs);
break;
+ case BIT_AND_EXPR:
+ /* A bit-and expression is as aligned as the maximum alignment of the
+ operands. We typically get here for a complex lhs and a constant
+ negative power of two on the rhs to force an explicit alignment, so
+ don't bother looking at the lhs. */
+ this_alignment = known_alignment (TREE_OPERAND (exp, 1));
+ break;
+
case ADDR_EXPR:
this_alignment = expr_align (TREE_OPERAND (exp, 0));
break;