From: Ian Romanick Date: Sat, 15 Dec 2012 22:49:53 +0000 (-0800) Subject: glsl: Allow elimination of uniform block members X-Git-Url: https://git.libre-soc.org/?a=commitdiff_plain;h=32f322925592e9eeda6a5624c7320232fc170c03;p=mesa.git glsl: Allow elimination of uniform block members glGetActiveUniform is not supposed to report block members that are not active even if they are included in the layout of the block. The block layout is determined from the GLSL_TYPE_INTERFACE that defines the block, so eliminating the ir_variables that correspond to the individual fields is safe. Fixes gles3conform test uniform_buffer_object_getuniformindices_for_for_nonexistent_or_not_active_uniform_names. This also fixes the assertion failures (added in the previous commit) in gles3conform uniform_buffer_object_index_of_not_active_block, uniform_buffer_object_inherit_and_override_layouts, and uniform_buffer_object_repeat_global_scope_layouts. Signed-off-by: Ian Romanick Reviewed-by: Jordan Justen --- diff --git a/src/glsl/opt_dead_code.cpp b/src/glsl/opt_dead_code.cpp index 78d31cfcb3f..b65e5c2ce33 100644 --- a/src/glsl/opt_dead_code.cpp +++ b/src/glsl/opt_dead_code.cpp @@ -98,15 +98,10 @@ do_dead_code(exec_list *instructions, bool uniform_locations_assigned) /* uniform initializers are precious, and could get used by another * stage. Also, once uniform locations have been assigned, the * declaration cannot be deleted. - * - * Also, GL_ARB_uniform_buffer_object says that std140 - * uniforms will not be eliminated. Since we always do - * std140, just don't eliminate uniforms in UBOs. */ if (entry->var->mode == ir_var_uniform && (uniform_locations_assigned || - entry->var->constant_value || - entry->var->is_in_uniform_block())) + entry->var->constant_value)) continue; entry->var->remove();