From: Torbjorn Granlund Date: Mon, 5 Oct 1998 00:08:56 +0000 (+0200) Subject: expmed.c (expand_divmod): Don't widen for computing remainder if we seem to have... X-Git-Url: https://git.libre-soc.org/?a=commitdiff_plain;h=32fdf36bb633d048c30d8be6c5e45ffef024e440;p=gcc.git expmed.c (expand_divmod): Don't widen for computing remainder if we seem to have a divmod pattern for... * expmed.c (expand_divmod): Don't widen for computing remainder if we seem to have a divmod pattern for needed mode. From-SVN: r22828 --- diff --git a/gcc/ChangeLog b/gcc/ChangeLog index 929c4b14547..fa5a057bd5b 100644 --- a/gcc/ChangeLog +++ b/gcc/ChangeLog @@ -1,3 +1,8 @@ +Mon Oct 5 01:07:23 1998 Torbjorn Granlund + + * expmed.c (expand_divmod): Don't widen for computing remainder + if we seem to have a divmod pattern for needed mode. + Mon Oct 5 01:01:42 1998 Zack Weinberg * cpplib.c (macroexpand): Correct off-by-one error in handling diff --git a/gcc/expmed.c b/gcc/expmed.c index 734365f8d35..f9bd9ad20be 100644 --- a/gcc/expmed.c +++ b/gcc/expmed.c @@ -3709,10 +3709,22 @@ expand_divmod (rem_flag, code, mode, op0, op1, target, unsignedp) if (rem_flag) { - /* Try to produce the remainder directly without a library call. */ - remainder = sign_expand_binop (compute_mode, umod_optab, smod_optab, - op0, op1, target, - unsignedp, OPTAB_WIDEN); + /* Try to produce the remainder without producing the quotient. + If we seem to have a divmod patten that does not require widening, + don't try windening here. We should really have an WIDEN argument + to expand_twoval_binop, since what we'd really like to do here is + 1) try a mod insn in compute_mode + 2) try a divmod insn in compute_mode + 3) try a div insn in compute_mode and multiply-subtract to get + remainder + 4) try the same things with widening allowed. */ + remainder + = sign_expand_binop (compute_mode, umod_optab, smod_optab, + op0, op1, target, + unsignedp, + ((optab2->handlers[(int) compute_mode].insn_code + != CODE_FOR_nothing) + ? OPTAB_DIRECT : OPTAB_WIDEN)); if (remainder == 0) { /* No luck there. Can we do remainder and divide at once