From: Connor Abbott <cwabbott0@gmail.com>
Date: Fri, 1 Aug 2014 01:57:23 +0000 (-0700)
Subject: ra: optimistically color only one node at a time
X-Git-Url: https://git.libre-soc.org/?a=commitdiff_plain;h=e78a01d5e6f77e075fe667a0f0ccb10d89c0dd58;p=mesa.git

ra: optimistically color only one node at a time

Before, when we encountered a situation where we had to optimistically
color a node, we would immediately give up and push all the remaining
nodes on the stack in the order of their index - which is a random, and
potentially not optimal, order. Instead, choose one node to
optimistically color in ra_select(), and then once we've optimistically
colored it, keep on going as normal in the hopes that we've opened up
more avenues for the normal select phase to make progress. In cases with
high register pressure, this helps make the order we push things on the
stack much better, and therefore increase the chance that we can allocate
successfully.

total instructions in shared programs: 4545447 -> 4545401 (-0.00%)
instructions in affected programs:     1353 -> 1307 (-3.40%)
GAINED:                                124
LOST:                                  6

Signed-off-by: Connor Abbott <connor.abbott@intel.com>
Reviewed-by: Eric Anholt <eric@anholt.net>
---

diff --git a/src/mesa/program/register_allocate.c b/src/mesa/program/register_allocate.c
index 4c17de789c5..d81a47f24a7 100644
--- a/src/mesa/program/register_allocate.c
+++ b/src/mesa/program/register_allocate.c
@@ -444,11 +444,12 @@ decrement_q(struct ra_graph *g, unsigned int n)
  * trivially-colorable nodes into a stack of nodes to be colored,
  * removing them from the graph, and rinsing and repeating.
  *
- * Returns true if all nodes were removed from the graph.  false
- * means that either spilling will be required, or optimistic coloring
- * should be applied.
+ * If we encounter a case where we can't push any nodes on the stack, then
+ * we optimistically choose a node and push it on the stack. We heuristically
+ * push the node with the lowest total q value, since it has the fewest
+ * neighbors and therefore is most likely to be allocated.
  */
-static bool
+static void
 ra_simplify(struct ra_graph *g)
 {
    bool progress = true;
@@ -457,6 +458,9 @@ ra_simplify(struct ra_graph *g)
    while (progress) {
       progress = false;
 
+      unsigned int best_optimistic_node = ~0;
+      unsigned int lowest_q_total = ~0;
+
       for (i = g->count - 1; i >= 0; i--) {
 	 if (g->nodes[i].in_stack || g->nodes[i].reg != NO_REG)
 	    continue;
@@ -467,16 +471,23 @@ ra_simplify(struct ra_graph *g)
 	    g->stack_count++;
 	    g->nodes[i].in_stack = true;
 	    progress = true;
+	 } else {
+	    unsigned int new_q_total = g->nodes[i].q_total;
+	    if (new_q_total < lowest_q_total) {
+	       best_optimistic_node = i;
+	       lowest_q_total = new_q_total;
+	    }
 	 }
       }
-   }
 
-   for (i = 0; i < g->count; i++) {
-      if (!g->nodes[i].in_stack && g->nodes[i].reg == -1)
-	 return false;
+      if (!progress && best_optimistic_node != ~0) {
+	 decrement_q(g, best_optimistic_node);
+	 g->stack[g->stack_count] = best_optimistic_node;
+	 g->stack_count++;
+	 g->nodes[best_optimistic_node].in_stack = true;
+	 progress = true;
+      }
    }
-
-   return true;
 }
 
 /**
@@ -537,34 +548,10 @@ ra_select(struct ra_graph *g)
    return true;
 }
 
-/**
- * Optimistic register coloring: Just push the remaining nodes
- * on the stack.  They'll be colored first in ra_select(), and
- * if they succeed then the locally-colorable nodes are still
- * locally-colorable and the rest of the register allocation
- * will succeed.
- */
-static void
-ra_optimistic_color(struct ra_graph *g)
-{
-   unsigned int i;
-
-   for (i = 0; i < g->count; i++) {
-      if (g->nodes[i].in_stack || g->nodes[i].reg != NO_REG)
-	 continue;
-
-      g->stack[g->stack_count] = i;
-      g->stack_count++;
-      g->nodes[i].in_stack = true;
-   }
-}
-
 bool
 ra_allocate(struct ra_graph *g)
 {
-   if (!ra_simplify(g)) {
-      ra_optimistic_color(g);
-   }
+   ra_simplify(g);
    return ra_select(g);
 }