ios = []
for pin in pins:
pname = "gpio"+pin[:-1] # strip "*" on end
- pads = []
# urrrr... tristsate and io assume a single pin which is
# of course exactly what we don't want in an ASIC: we want
# *all three* pins but the damn port is not outputted
# as a triplet, it's a single Record named "io". sigh.
# therefore the only way to get a triplet of i/o/oe
# is to *actually* create explicit triple pins
- pads.append(Subsignal("i",
- Pins(pname+"_i", dir="i", assert_width=1)))
- pads.append(Subsignal("o",
- Pins(pname+"_o", dir="o", assert_width=1)))
- pads.append(Subsignal("oe",
- Pins(pname+"_oe", dir="oe", assert_width=1)))
- ios.append(Resource.family(pname, 0, default_name=pname,
- ios=pads))
+ pad = Subsignal("io",
+ Pins("%s_i %s_o %s_oe" % (pname, pname, pname),
+ dir="io", assert_width=3))
+ ios.append(Resource(pname, 0, pad))
resources.append(Resource.family(periph, 0, default_name="gpio",
ios=ios))
gpio = platform.request('gpio')
print (gpio, gpio.layout, gpio.fields)
# get the GPIO bank, mess about with some of the pins
- m.d.comb += gpio.gpio0.o.eq(1)
- m.d.comb += gpio.gpio1.o.eq(gpio.gpio2.i)
- m.d.comb += gpio.gpio1.oe.eq(count[4])
- m.d.sync += count[0].eq(gpio.gpio1.i)
+ m.d.comb += gpio.gpio0.io.o.eq(1)
+ m.d.comb += gpio.gpio1.io.o.eq(gpio.gpio2.io.i)
+ m.d.comb += gpio.gpio1.io.oe.eq(count[4])
+ m.d.sync += count[0].eq(gpio.gpio1.io.i)
# get the UART resource, mess with the output tx
uart = platform.request('uart')
print (uart, uart.fields)
if pin is None: continue # skip when pin is None
assert corepin is not None # if pad was None, core should be too
print ("iter", pad, pin.name)
+ print ("existing pads", self.padlookup.keys())
assert pin.name not in self.padlookup # no overwrites allowed!
assert pin.name == corepin.name # has to be the same!
self.padlookup[pin.name] = pad # store pad by pin name