src/gallium/drivers/nouveau/nouveau_util.h

   1 #ifndef __NOUVEAU_UTIL_H__
   2 #define __NOUVEAU_UTIL_H__
   3
   4 /* Determine how many vertices can be pushed into the command stream.
   5  * Where the remaining space isn't large enough to represent all verices,
   6  * split the buffer at primitive boundaries.
   7  *
   8  * Returns a count of vertices that can be rendered, and an index to
   9  * restart drawing at after a flush.
  10  */
  11 static INLINE unsigned
  12 nouveau_vbuf_split(unsigned remaining, unsigned overhead, unsigned vpp,
  13                    unsigned mode, unsigned start, unsigned count,
  14                    unsigned *restart)
  15 {
  16         int max, adj = 0;
  17
  18         max  = remaining - overhead;
  19         if (max < 0)
  20                 return 0;
  21
  22         max *= vpp;
  23         if (max >= count)
  24                 return count;
  25
  26         switch (mode) {
  27         case PIPE_PRIM_POINTS:
  28                 break;
  29         case PIPE_PRIM_LINES:
  30                 max = max & 1;
  31                 break;
  32         case PIPE_PRIM_TRIANGLES:
  33                 max = max - (max % 3);
  34                 break;
  35         case PIPE_PRIM_QUADS:
  36                 max = max & 3;
  37                 break;
  38         case PIPE_PRIM_LINE_LOOP:
  39         case PIPE_PRIM_LINE_STRIP:
  40                 if (max < 2)
  41                         max = 0;
  42                 adj = 1;
  43                 break;
  44         case PIPE_PRIM_POLYGON:
  45         case PIPE_PRIM_TRIANGLE_STRIP:
  46         case PIPE_PRIM_TRIANGLE_FAN:
  47                 if (max < 3)
  48                         max = 0;
  49                 adj = 2;
  50                 break;
  51         case PIPE_PRIM_QUAD_STRIP:
  52                 if (max < 4)
  53                         max = 0;
  54                 adj = 3;
  55                 break;
  56         default:
  57                 assert(0);
  58         }
  59
  60         *restart = start + max - adj;
  61         return max;
  62 }
  63
  64 #endif